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3 years ago

12

Help me please!! asap (LOOK AT ALL THE PHOTOS)

1 answer:

Lynna [10]3 years ago

5 0

Answer:

6 and 24

Step-by-step explanation:

Replace the t with 1

3 x 2^1 = 6

3 x 2^3 = 24

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If you toss a coin 4 times, what is the probability of landing heads, heads, tails, heads and then heads?

storchak [24]

50 percent chance for either one

7 0

4 years ago

Read 2 more answers

Determine the quadratic function of 2,-3/5

Tanzania [10]

I guess you mean that the zeroes are 2 and -3/5.

In factor form the function could be

f(x) = (x - 2)(3x + 5)

expanding we get

f(x) = 3x^2 -x - 10

6 0

4 years ago

Solomon has read 1/3 of his book. He finishes the book by reading the same amount each night for 5 nights.

Nadusha1986 [10]

Answer:

A - Solomon read $\frac{2}{15}$ of the book each night.

B - The total number of pages in the book are 105.

Step-by-step explanation:

We are given that,

Solomon has read $\frac{1}{3}$ of a book.

So, $1-\frac{1}{3}=\frac{2}{3}$ of the book is left to be read.

Ques A: We have that,

In 5 nights, Solomon read $\frac{2}{3}$ of the book.

So, on 1 night, he will read, $\frac{2}{3}\times \frac{1}{5}$ = $\frac{2}{15}$ of the book.

Thus, Solomon read $\frac{2}{15}$ of the book each night.

Ques B: Let the total pages of the book = x.

Solomon reads 14 pages in 1 night. So, he reads, 14 × 5 = 70 pages in 5 nights.

Since, these 70 pages represent the $\frac{2}{3}$ of the book, he read in 5 nights.

So, $\frac{2}{3}$ of the total pages = 70

i.e. $\frac{2}{3}x=70$

i.e. x= 105

Hence, the total number of pages in the book are 105.

7 0

4 years ago

Jane is making a suit which requires 2 5/8yards for the jacket and 13/4 yards for the skirt.

Lemur [1.5K]

I honestly dont know what to solve?

5 0

3 years ago

Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

3 0

4 years ago