Answer:
=k=0.25h-7/12
Step-by-step explanation:
4(h-3k)=h+7
=4h-12k=h+7
collecting like terms and leaving characters with k on 1 side, we get;
12k=3h-7
=k=0.25h-7/12
Answer:
(0, 4 ) and (2, - 4 )
Step-by-step explanation:
(2)
3x + 4y = 16 → (1)
- 3x + 2y = 8 → (2)
Adding (1) and (2) term by term will eliminate the x- term
0 + 6y = 24
6y = 24 ( divide both sides by 6 )
y = 4
Substitute y = 4 into either of the 2 equations and solve for x
Substituting into (1)
3x + 4(4) = 16
3x + 16 = 16 ( subtract 16 from both sides )
3x = 0 , then
x = 0
solution is (0, 4 )
(3)
2x - 4y = 20 → (1)
5x + 4y = - 6 → (2)
Adding (1) and (2) term by term will eliminate the y- term
7x + 0 = 14
7x = 14 ( divide both sides by 7 )
x = 2
Substitute x = 2 into either of the 2 equations and solve for y
Substituting into (2)
5(2) + 4y = - 6
10 + 4y = - 6 ( subtract 10 from both sides )
4y = - 16 ( divide both sides by 4 )
y = - 4
solution is (2, - 4 )
This problem calls for application of the distributive rule for multiplication.
<span>3w(p +18) can be expanded to 3wp + 54w.</span>
1234 multiplied by 0.22(22%) equals 271.48.
1234-271.48=962.52(A)
Answer: There are 400 tadpoles in the year 1994.
This is because any point is of the form (x,y) where in this case
x = year number
y = tadpole population number
So (x,y) = (1994, 400) means x = 1994 and y = 400 pair up together.
In short, the year x = 1994 corresponds to the population of y = 400 tadpoles.
From the years 1990 to 1992, the population is increasing since the curve goes upward when moving from left to right. Then from 1992 to 1993, the population decreases hitting its lowest point in that specific region. From 1993 to 1997, the population increases before it decreases again from 1997 to 1999.
