Answer:
Because
Step-by-step explanation:
4 4/10 = 4.4 and 32/10 = 3.2
4.4 is bigger than 3.2 so that's why 4 4/10 is bigger.
Answer: 0.951%
Explanation:Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.
Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).
Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or
0.951%.
Answer:
A
Step-by-step explanation:
Have a great day!!!!!
T=4(r-1.5)
4(3.59-1.5)=t= 8.36 dolla
Enjoy.
“Vertical translation up” because the parents fuction which is the f(x) is equal to x^2