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bija089 [108]
3 years ago
8

What is the most vulnerable information that should be protected to prevent unauthorized access to your online files and records

?
Computers and Technology
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

Your user ID and password.

Explanation:

The user Id and password must be protected because when it is exposed to a third party then they can get access to information, data, to things they are not supposed to.

The user Id and password is provided as an authentication measure for one to be able to gain access to a computer system, network or files. It is what grants access to online files and record as it is the case here. It has to be protected for the sake of privacy.

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assuming the default gateway is connected to the internet, what type of internet access would this server have?
erik [133]

If the default gateway is connected to the internet, the type of internet access that the server would have is:

  • Full Access

<h3>What is a Default Gateway?</h3>

A default gateway is a functionality in a computer system that allows access or communication with other networks.

It is the primary channel of interaction with other networks. Once this default gateway is connected to the internet, it will be given full access.

Learn more about the default gateway here:

brainly.com/question/2692918

#SPJ11

3 0
2 years ago
Remember partially filled arrays where the number of elements stored in the array can be less than its capacity (the maximum num
MrMuchimi

Answer:

Complete the main method as follows:

int num;

cin>>num;

int i = 0;

while(num!=0){

array[i] = num;  

cin>>num;

i++;

}

Complete the printArray function as follows:

void printArray(int array[]){

int i =0;

while(array[i]!=0){

   cout<<array[i]<<" ";

   i++;

}}

Explanation:

<u>Main method</u>

This declares a variable that gets input from the user

int num;

This gets input from the user

cin>>num;

This initializes a count variable to 0. It represents the index of the current array element

int i = 0;

while(num!=0){

This inserts the inputted number to the array

array[i] = num;

This gets another input  

cin>>num;

The counter is incremented by 1

i++;

}

The above loop is repeated until the users enters 0

<u>printArray method</u>

This declares the array

void printArray(int array[]){

This initializes a counter variable to 0

int i =0;

This is repeated until array element is 0

while(array[i]!=0){

Print array element

   cout<<array[i]<<" ";

Increase counter by 1

   i++;

}}

<em>See attachment for complete program</em>

Download cpp
8 0
3 years ago
Write a Python program that will take as input 5 integer values and will output the average of the odd values and the average of
8_murik_8 [283]

Code:

Here is the code. Also screenshot of the code and text file containing the code have been attached here.

This code has been written in Python 3.0

# getting input

lst = [ ]  

n = 5  

for i in range(0, n):  

   ele = int(input())  

   lst.append(ele)

print(lst)

# getting odd numbers and even numbers from list and compute average

odd_sum = 0

even_sum = 0

odd = 0

even = 0

for i in range(0, n):  

   if lst[i] % 2 == 0:

       even_sum = even_sum + lst[i]

       even = even + 1

   elif lst[i] % 2 > 0:

       odd_sum = odd_sum + lst[i]

       odd = odd + 1

       

odd_avg = odd_sum/odd

even_avg = even_sum/even

print("there were",odd,"odd numbers in input")

print("there were",even,"odd numbers in input")

print("average of odd numbers in the list",odd_avg)

print("average of even numbers in the list",even_avg)

6 0
3 years ago
Two floating point numbers, A and B, are passed to a recursive subroutine.
Mnenie [13.5K]
The answer is (c) infinite loop
6 0
4 years ago
Public static void prefixmerge(customer[] list1, customer[] list2, customer[] result {
White raven [17]
I can't get what do you need, but I guess it's a part of java code. I can explain what it means. It's used to unite two rising sorted arrays which are list1 and list2. The result is stored in result array. I suggest you to clearly explain your task as it's difficult to give you correct answer.
8 0
4 years ago
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