Find the area of the rectangle and the 1/2 circle, then subtract the half circle's area from the rectangle's.
Area of the rectangle is 30in.
Area of the 1/2 circle is 19.625.
Subtract
30-19.625
10.375
(Round it to 10.4 in this case)
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.
When we are attempting limits questions, there are several tests we attempt first.
1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)


4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.
For example:
1)

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>Substitute x = 0 to the function.


<em>Method 2: Rearranging the function
</em>We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.



Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
Answer:
$75
Step-by-step explanation:
First, we will find how many hours he worked. 8:00-12:00 is 4 hours, and 12:00-2:00 is 2 hours, so he worked a total of 6 hours.
Next, we have to multiply the hours worked by his hourly wage.
12.50*6=75
Answer:
Horizontal distance between the log and the bridge when the stone is released = 17.24 m
Step-by-step explanation:
Height of bridge, h = 50.8 m
Speed of log = 5.36 m/s
We need to find the horizontal distance between the log and the bridge when the stone is released, for that first we need to find time taken by the stone to reach on top of log,
We have equation of motion. s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 50.8 m
Substituting,
s = ut + 0.5 at²
50.8 = 0.5 x 9.81 x t²
t = 3.22 seconds,
So log travels 3.22 seconds at a speed of 5.36 m/s after the release of stone,
We have equation of motion. s = ut + 0.5 at²
Initial velocity, u = 5.36 m/s
Acceleration, a = 0 m/s²
Time, t = 3.22 s
Substituting,
s = ut + 0.5 at²
s = 5.36 x 3.22 + 0.5 x 0 x 3.22²
s = 17.24 m
Horizontal distance between the log and the bridge when the stone is released = 17.24 m
Answer:
2:15 PM
Step-by-step explanation:
When the plane arrives in Seattle, the time in eastern time period would be 5:15 PM. From eastern to pacific, the time goes back 3 hours. 5:15 - 3 hours is 2:15. Since the time is still in the afternoon, it is still PM.