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3 years ago

If the length and breadth of a rectangle are 10cm and 20cm respectively,find the length of its diagonal

Mathematics

2 answers:

weqwewe [10]3 years ago

6 0

Answer:22.4 cm

Step-by-step explanation:

First draw the rectangle and divide it into two triangles.

Take one triangle out and with the length and breath solve for the hypotenuse using Pythagoras theorem

.: H^2 = 10^2 + 20^2

H^2 = 500

Find the square root of both sides of the equation

H = 22.4 cm = the length of the diagonal

irina [24]3 years ago

5 0

L = 10

B = 20

so to find the diagonal you have to use Pythagorean theorem that is a^2 + b^2 = c^2

10^2 + 20^2 = X^2

X = root of 10^2 + 20^2

X = root of 100 + 400

X = root of 500

X = appox 22.36

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Which expression is equivalent to $\frac{4mn}{m^{-2}n^6}$ . Assuming $m \neq 0; n\neq 0$

Answer:

$\frac{4m^3}{n^5}$

Step-by-step explanation:

Given

$\frac{4mn}{m^{-2}n^6}$

Required:

Simplify

To simplify this, we start by splitting each individual function

$\frac{4mn}{m^{-2}n^6} = \frac{4m}{m^{-2}} * \frac{n}{n^6}$

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