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Serga [27]
3 years ago
15

Select the circumference and area for the circle to the nearest hundredth. Use 3.14 for pi

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

Area:  A = πr2

A = 3.14(2.5955414)2

A = 21.15366242 in2

Step-by-step explanation:

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Isabella is having going to the movies with some friends each friend get 6/8 cups of popcorn if there are 7 friends at the movie
aev [14]
5.25 cups of popcorn. 

You will get this by multiplying the total number of friends by how much popcorn each of them is getting.
8 0
4 years ago
???????????????!!!!!!!!
Zigmanuir [339]

Answer:

m ∠ L = 54°

Step-by-step explanation:

the angles of triangle are 2x, 3x & 5x

the sum of angles are 180°

2x+3x+5x = 180

10x = 180

x = 180/10 = 18°

m ∠ L = 3x° = 3(18)° = 54°

m ∠ L = 54°

3 0
3 years ago
1 yard =3 feet and 1 foot =12 inches
AysviL [449]

Answer:

54 yds=162 ft, 1944 in

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, 54 yds*3 ft=162 ft

162 ft*12 in=1944 in

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

Please, please give brainliest, it would be greatly appreciated, I only a few more before I advance, thanks!

3 0
3 years ago
I need help with problem 1 with a through explanation and solution please <br><br>​
ki77a [65]

Explanation:

The cubic ...

  f(x) = ax³ +bx² +cx +d

has derivatives ...

  f'(x) = 3ax² +2bx +c

  f''(x) = 6ax +2b

<h3>a)</h3>

By definition, there will be a point of inflection where the second derivative is zero (changes sign). The second derivative is a linear equation in x, so can only have one zero. Since it is given that a≠0, we are assured that the line described by f''(x) will cross the x-axis at ...

  f''(x) = 0 = 6ax +2b   ⇒   x = -b/(3a)

The single point of inflection is at x = -b/(3a).

__

<h3>b)</h3>

The cubic will have a local extreme where the first derivative is zero and the second derivative is not zero. These will only occur when the discriminant of the first derivative quadratic is positive. Their location can be found by applying the quadratic formula to the first derivative.

  x=\dfrac{-2b\pm\sqrt{(2b)^2-4(3a)(c)}}{2(3a)} = \dfrac{-2b\pm\sqrt{4b^2-12ac}}{6a}\\\\x=\dfrac{-b\pm\sqrt{b^2-3ac}}{3a}\qquad\text{extreme point locations when $b^2>3ac$}

There will be zero or two local extremes. A local extreme cannot occur at the point of inflection, which is where the formula would tell you it is when there is only one.

__

<h3>c)</h3>

Part A tells you the point of inflection is at x= -b/(3a).

Part B tells you the midpoint of the local extremes is x = -b/(3a). (This is half the sum of the x-values of the extreme points.) You will notice these are the same point.

The extreme points are located symmetrically about their midpoint, so are located symmetrically about the point of inflection.

_____

Additional comment

There are other interesting features of cubics with two local extremes. The points where the horizontal tangents meet the graph, together with the point of inflection, have equally-spaced x-coordinates. The point of inflection is the midpoint, both horizontally and vertically, between the local extreme points.

6 0
3 years ago
If G^-1(x) is the inverse of G(x), what is the value of G^-1(G(x))?
Ber [7]

Answer:

G^{-1}(G(x))=x

Step-by-step explanation:

Definition: Let f be one-to-one function with the domain A and  the range B. Then the inverse function f^{-1} has the domain B and the range A and is defined as

f^{-1}(y)=x\ \Leftrightarrow \ f(x)=y

Facts:

1) For every x\in A:

f^{-1}(f(x))=x

2) For every y\in B:

f(f^{-1}(y))=y

So, G^{-1}(G(x))=x

5 0
4 years ago
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