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3 years ago

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A chemical company makes two brands of antifreeze the first brand contains 65% pure antifreeze and the second brand contains 80%

pure antifreeze in order to obtain 60 gallons of a mixture that contains 70% pure antifreeze how many gallons of each brand of antifreeze must be used

1 answer:

liq [111]3 years ago

8 0

Answer:

30 gallons of each brand

Step-by-step explanation:

1 gallon of 60% + 1 gallon of 80% = 2 gallons 70% (60/2 = 30)

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Paha777 [63]

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$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

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The values of $\sin 2x, \cos 2x, \tan 2x$ .

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We know that,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

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Hence, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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