The sum if the geometric sequence given by:
an=-2(3)^(n-1)
will be:
when:
n=1
an=-2
when n=2
a2=-6
when n=3
a3=-18
when n=4
a4=-54
when n=5
a5=-162
when n=6
a6=-486
when n=7
a7=-1458
when n=8
a8=-4374
thus the summation of the term will be:
Sn=(-4374+-1458+-486+-162+-54+-18+-6+-2)
Sn=-6560
the answer is -6560
= -30a^5b + 12a^4b^3 + 6a^3b^2 + 10a^3b^2 - 4a^2b^4 - 2ab^3
= -30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2ab^3
answer
B. -30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2ab^3
Answer:
1.125 or 9/8
Step-by-step explanation:
5/8 is .625 and 3/6 is .5 so .625+.5=1.125
Answer:
1. -√19 2. 4.56 3. √21 4. 23/5
Step-by-step explanation:
