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Colt1911 [192]
3 years ago
6

How to solve -2p^2=16p+24

Mathematics
1 answer:
frozen [14]3 years ago
8 0

Add  2p²  to each side of the equation.  Then you have

                 2p² + 16p + 24  =  0 .

Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by  2 .  Then you have:

                 p² + 8p + 12 = 0 .

Now you have a nice, comfortable, familiar-looking quadratic equation. 
You can either factor the left side into  (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.

That's how to solve it, and find its two solutions.


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If 1/2 cup of fruit cocktail contains 13g of sugar, then 1 1/4 cup of fruit cocktail contains how many grams of sugar?
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Answer : 32.5 g of sugar

Step-by-step explanation:

1 1/4 cup = (4+1)/4 = 5/4 cup

If 1/2 cup contains 13 g of sugar

Then 5/4 cup contains C g of sugar

C = 5/4 * 13g➗1/2 = 5*13*2g➗4 = 130g➗4 = 32.5 g of sugar

Answer : 32.5 g of sugar

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Select ALL the correct answers.
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Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0
2 years ago
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