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Colt1911 [192]
3 years ago
6

How to solve -2p^2=16p+24

Mathematics
1 answer:
frozen [14]3 years ago
8 0

Add  2p²  to each side of the equation.  Then you have

                 2p² + 16p + 24  =  0 .

Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by  2 .  Then you have:

                 p² + 8p + 12 = 0 .

Now you have a nice, comfortable, familiar-looking quadratic equation. 
You can either factor the left side into  (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.

That's how to solve it, and find its two solutions.


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luda_lava [24]
You could do :
Johnny was financing a limited editions Xbox One S. The price was $420 and he put down 40%. How much is left to be financed?
dp=420(40/100)=16800/100=168
then you would subtract 420-168 which would give you 252
;) good luck !!
3 0
2 years ago
Mrs. Austin teaches forty-eight students. One-third of her students are out sick with the flu. How many students are sick?
Aneli [31]
16 of the students are sick. How I got this was, divide 48 by 3 and you get 16 therefore 1/3 of 48 is 16.
8 0
2 years ago
There are 36 students in Mrs.Keatons's sixth grade class. If 5/12 of her students are girls, how many girls in the class?
murzikaleks [220]
There are 15 girls because 12 x 3 = 36 and 5 x 3 = 15
6 0
3 years ago
Ill give brainliest - please help ASAP<br><br> WITH THE WORK THO PLEASE?
ohaa [14]

Answer:

5.

we have.

11x=½(16x+16+50)

22x=16x+66

22x-16x=66

6x=66

x=66/6

x=11

6.

118°=½(6x-11+181)

236=6x+170

6x=236-170

x=66/6

x=11°

7.

34°=½(arcAK-arc LN)

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4 0
3 years ago
A community swimming pool is a rectangular prism that is 30 feet long, 12 feet wide, and 5 feet deep. The wading pool is half as
topjm [15]

Answer:

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

Step-by-step explanation:

By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:

Community swimming pool

V_{c} = l\cdot w\cdot h (1)

Wading pool

V_{w} = \left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w (2)

Where:

l – Length of the swimming pool, measured in feet.

h – Depth of the swimming pool, measured in feet.

w – Width of the swimming pool, measured in feet.

V_{c} – Volume of the community swimming pool, measured in cubic feet.

V_{w} – Volume of the wading swimming pool, measured in cubic feet.

The ratio of the volume of the community swimming pool to the volume of the wadling pool is:

\frac{V_{c}}{V_{w}} = \frac{l\cdot w \cdot h}{\left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w} (3)

\frac{V_{c}}{V_{w}} = \frac{1}{\frac{1}{4} }

\frac{V_{c}}{V_{w}} = 4

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

8 0
2 years ago
Read 2 more answers
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