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3 years ago

Yall can someone plz do this for me I would really appreciate it I'll give all of my points

Mathematics

1 answer:

ycow [4]3 years ago

6 0

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A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries. Ramses

drek231 [11]

Answer:

System of inequalities:

$3x+2y \leq 25$ , $4x+6y \leq 37$

1) Maximum number of sundaes possible = 9

2) Maximum number of milkshakes possible = 6

3) Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.

Step-by-step explanation:

Given : A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries.

Ramses wants to make sundaes and milkshakes with at most 25 ice-cream scoops and 37 strawberries.

Let x denote the number of sundaes he makes and y the number of milkshakes he makes.

First we represent in tabular form,

Sundae(x) Milkshake(y) Total

Ice-cream 3 2 3x+2y

Strawberries 4 6 4x+6y

→System of inequalities:

Sundaes and milkshake with at most 25 ice-cream scoops= $3x+2y \leq 25$

Sundaes and milkshakes with at most 37 strawberries = $4x+6y \leq 37$

→ Plotting the equations in the graph (figure attached)

1) Maximum number of sundaes possible:

Maximum no. of sundaes possible when y=0

From the graph y=0 at x=9.25

Therefore, Maximum number of sundaes possible is 9

2) Maximum number of milkshakes possible:

Maximum no. of milkshakes possible when x=0

From the graph x=0 at y= 6.167

Therefore, Maximum number of milkshakes possible is 6

3) Combination that uses the most of both Ice-cream and Strawberries:

Combination of both is possible there is a intersection of both the equation

From the graph intersection point is x=7.6 and y=1.1

Therefore, Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.

5 0

3 years ago

What is the value of 2(-6) + 3(7)

tino4ka555 [31]

The value would be 9

7 0

3 years ago

Read 2 more answers

A box of volume 180 m3 with square bottom and no top is constructed out of two different materials. The cost of the bottom is $4

zysi [14]

Answer:

Side of square bottom=6.46 m

Height of box=4.31 m

Step-by-step explanation:

Let s be the side bottom

Height of box=h

Volume of box= $180m^3$

Volume of box= $lbh=s^2h$

$s^2h=180$

$h=\frac{180}{s^2}$

Cost of bottom=$40 per square m

Cost of sides =$30 per square m

Total cost= $C=40s^2+30(4sh)$

$C=40s^2+120s\times \frac{180}{s^2}$

$C(s)=40s^2+\frac{21600}{s}$

Differentiate w.r.t s

$C'(s)=80s-\frac{21600}{s^2}$

$C'(s)=0$

$80s-\frac{21600}{s^2}=0$

$80s=\frac{21600}{s^2}$

$s^3=\frac{21600}{80}=270$

$s=(270)^{\frac{1}{3}}=6.46$

Again,differentiate w.r.t s

$C''(s)=80+\frac{43200}{s^3}$

Substitute s=6.46

$C''(6.46)=80+\frac{43200}{(6.46)^3}=240.2>0$

Hence, the cost is minimum at s=6.46

$h=\frac{180}{s^2}=\frac{180}{(6.46)^2}=4.31$

Side of square bottom=6.46 m

Height of box=4.31 m

5 0

3 years ago

Somebody please help!

m_a_m_a [10]

Answer: You need to combine like terms the answer is 2y+2x

5 0

3 years ago

Read 2 more answers

2. If a seamstress is paid $7.85 per hour and works 18.75 hours in one week, how much is she paid for that week? A. $147.19 B. $

ExtremeBDS [4]

The seamstress is paid A. $147.19 for that week

6 0

3 years ago