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3 years ago

6

How do you solve u/6 > (with an underline underlining it) 3 plz help its due tomorrow

1 answer:

vlada-n [284]3 years ago

8 0

To find the answer of u, simplify:

u>=6 × 3
u>= 18

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On Sunday a library checked out 52books .if 24 of the books were fiction what is the ratio of non fiction books to fiction books

lana66690 [7]

Answer:

Ratio of Non Fiction : Fiction books = 7 : 6

Step-by-step explanation:

Total number of books checked out = 52

Number of fiction books checked out = 24

So, number of non fiction books = Total books - number of fiction books

Or, number of non fiction = 52 - 24 = 28 books

Now, ratio of Non Fiction : Fiction books = 28 : 24

Solving the ratio term in its lowest form, we get

The Ratio of Non Fiction : Fiction books = 7 : 6

7 0

3 years ago

A pair of pant and a t-shirt cost $25. If the pant cost $7.28 more than the shirt, how much did the pant cost?

Lena [83]

$16.14 =pants

Explanation:

$25-$7.28=17.72

17.72/2 =8.86

8.86+7.28=16.14

25-16.14=8.86 shirt

I hope that helped ..

4 0

3 years ago

Read 2 more answers

Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtai

Aneli [31]

Answer:

I cannot understand this question

Step-by-step explanation:

I don't know what is in the question

5 0

2 years ago

et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe

Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation $f(x)=x+\lvert 2x-3 \rvert=12$ can be solved as follows:

$x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}$

$\lvert 2x-3 \rvert =12-x$

$2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)$

$3x=15\,\,\text{or}\,\,\x=-9$

Then, the solutions of the equation are $x=5, x=-9$ .

Now, if $g(x)=5x-3+\lvert x+4\rvert$ , we can solve the equation $g(a)=4a+9$ as follows:

$5a-3+\lvert a+4 \rvert =4a+9$

$\lvert a+4\rvert =4a+9-5a+3$

$a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)$

$2a=8\,\,\text{or}\,\,4=12$

So, the unique solution of this last equation is $a=4$

The last equation is $h(x-1)=x-3$ , where $h(x)=\lvert x \rvert -2x+5.$ . To solve this equation we can proceed as follows:

$h(x-1)=x-3$

$\lvert x-1\rvert -2(x-1)+5=x-3$

$\lvert x-1 \rvert -2x+2+5=x-3$

$\lvert x-1\rvert =3x-10$

$x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)$

$-2x=-9\,\,\text{or}\,\,4x=11$

$x=9/2\,\,\text{or}\,\,x=11/4$

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0

3 years ago

How do you solve an equation when yhe variable is being divided by a whole number

valentinak56 [21]

For example, if x/2=7, x would be equal to 7x2=14, bringing the whole number the variable is divided by to the other side of the equation.

4 0

3 years ago