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2 years ago

Question in image again

Mathematics

2 answers:

Reil [10]2 years ago

7 0

16in I believe irdk
Hope it helped..

Snowcat [4.5K]2 years ago

4 0

Hello there!

I used a calculator for this problem, but it shows you the steps involved. The picture is included. I hope this helps!

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Find gcd for 5767 and 4453

Dima020 [189]

The gcd of 5767 and 4453 is 73.
Hope this helps. :)

7 0

3 years ago

Write an equation of the line that passes through (-1,4) and is perpendicular to the line shown.

Tatiana [17]

find the slope of the two points written in the graph ( slope = rise. )
———-
Run

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%2826%20%5Cdiv%20100%29%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Ctimes%2010" id

taurus [48]

Answer:

$\boxed{\bf \: \cfrac{13}{5}}$

Or in Decimal:

$\boxed{\bf \: 2.6}$

Step-by-step explanation:

Given expression :-

$\sf \: ( 26 \div 100) \times 10$

Solution :-

$\sf = (26 \div 100 )\times 10$

This arithmetic expression may be rewritten as ;

$\sf = \cfrac{26}{100} \times 10$

Step 1 : Cancel the zero of 10 and one zero of 100 :-

$\sf = \cfrac{26}{10 \cancel0} \times 1 \cancel0$

Results to;

$\sf = \: \cfrac{26}{10} \times 1$

$\sf = \: \cfrac{26}{10}$

Step 2: Cancel 26 and 10 by 2 :-

$\sf = \cfrac{ \cancel{26}}{ \cancel{10}}$

Results to;

$\sf = \cfrac{ \cancel{26} {}^{13} }{ \cancel{10} {}^{5} }$

$\sf = \cfrac{13}{5}$

It can also be in Decimal.

That is;

$\sf = 2.6$

Hence, the answer of the expression would be 13/5 or 2.6 .

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.

I am joyous to help!

3 0

3 years ago

Read 2 more answers

The coordinate plane below shows the graph of a linear function of x. Which of the following equations best describes the functi

Vitek1552 [10]

Answer: Its A

Step-by-step explanation:

5 0

2 years ago

What is the solution of -x+4>2

Svetradugi [14.3K]

There is no single solution but there is a group of solutions also known as the interval.

$-x+4>2 \\-x>-2 \\x$

This can be written with an interval.

$x\in(-\infty, 2)$

Hope this helps.

r3t40

6 0

3 years ago