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aleksandr82 [10.1K]

4 years ago

12

Simplify (2x^2y)^3 (-3xy^2)^2

1 answer:

solniwko [45]4 years ago

8 0

Simplified it's 576x^8y^7

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Solve the following equation algebraically: 3 x squared = 375 a. x almost-equals 49 b. x almost-equals plus-or-minus 49 c. x alm

d1i1m1o1n [39]

3x^2=375
x^2=125
x=11.18

c or d, they say the same thing

4 0

3 years ago

A sample of a radioactive isotope had an initial mass of 540 mg in the year 1991 and decays exponentially over time. A measureme

Doss [256]

Answer:

Y=200 (1-0.044)^t

5 0

3 years ago

Read 2 more answers

How could you represent 0.614 without<br> using hundredths?

jasenka [17]

Answer: You can either round to 0.6 or put in fraction form $\frac{307}{500}$

Step-by-step explanation:

8 0

2 years ago

Is 100 a good estimate for the difference of 712 and 589? If it is, explain why it is a good estimate. If it is not, explain why

Masja [62]

It is a bad estimate because the gap between 712 and 589 is clearly (if you were just estimating in hundreds) would be 200

200 would be a better guess

4 0

4 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$

4 0

3 years ago