Hi everyone,can someone help me find what -1+(-3)?
2 answers:
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Answer:
The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval
, we have the following confidence interval of proportions.
In which
Z is the zscore that has a pvalue of .
For this problem, we have that:
8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that .
95% confidence interval
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).
Answer: Please, see the attached file.
Thanks.
Solution:
We can graph using the intercepts:
(1) y-intercept, when x=0
y=4x-3→y=4(0)-3→y=0-3→y=-3
Point=(x,y)=(0,-3)
(2) x-intercept, when y=0
y=4x-3→0=4x-3
Solving for x: Adding 3 both sides of the equation:
0+3=4x-3+3
3=4x
Dividing both sides of the equation by 4:
3/4=4x/4
3/4=x
x=3/4=0.75
Point=(x,y)=(3/4,0)=(0.75,0)
With these pair of points (0, -3) and (0.75,0) we can draw the right line
