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erma4kov [3.2K]
2 years ago
8

0.09+ 100 27 ​ = 100 ​ + 100 27 ​

Mathematics
1 answer:
babunello [35]2 years ago
5 0

Answer:

x = 9#

Step-by-step explanation:

need help with answer just ask me i got yall

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Aiden buys a bag of cookies that contains 9 chocolate chip cookies, 8 peanut butter cookies, 8 sugar cookies and 9 oatmeal cooki
Airida [17]

The probability that Aiden randomly selects an oatmeal cookie from the bag, eats it, then randomly selects a chocolate chip cookie is 0.0721

<h3>How to determine the probability?</h3>

The distribution of the cookies is given as:

  • 9 chocolate chip cookies
  • 8 peanut butter cookies
  • 8 sugar cookies
  • 9 oatmeal cookies

When he eats a cookie, the number of cookies reduces by 1

So, the required probability is:

P(Oatmeal and Chocolate) = Oatmeal/Total * Chocolate/Total - 1

This gives

P(Oatmeal and Chocolate) = 9/(9 + 8 + 8 + 9) * 9/(9 + 8 + 8 + 9 -1)

Evaluate

P(Oatmeal and Chocolate) = 0.0721

Hence, the probability is 0.0721

Read more about probability at:

brainly.com/question/25870256

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5 0
2 years ago
14. Sarah swam 200 meters more than Molly.
mylen [45]

Answer:you add 200 to 800 and you get 1100

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is 8x + 10 ≤ 51 please show work
Vanyuwa [196]

\huge\fbox{Hi~there!~:)}

Let's solve this inequality! :)

Let's start by subtracting 10 from both sides:

\rm{8x\leq 51-10}

\rm{8x\leq 41

Now, divide both sides by 8:

x\leq \displaystyle\frac{41}{8} (Answer)

Decimal form:

\rm{5.125}

I hope you find it helpful.

Feel free to ask if you have any doubts.

\bf{-MistySparkles^**^* here to help

3 0
2 years ago
Kamal bought 7 packs of paper clips for a project. Then he bought 8 more packs. There are 25 paper clips in each pack. How many
Rasek [7]
The answer 375. the first 7 is 175 then add 200 to the 175 and that is how you get the full 8 more
3 0
3 years ago
Read 2 more answers
PLS HELP
scoundrel [369]

Answer:

book math and follow the instructions

Step-by-step explanation:

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3 0
2 years ago
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