Answer:
- Cos 45=6/x
x=6/cos 45=6√2
x=6√2
tan 45=y/6
y=tan45 ×6
y=6
2.
sin 60=y/10
y=sin60×10
y=5√3
again
Cos 60=x/10
x=½×10
x=5
3.
Sin 45=x/5
x=1/√2×5 or
x=5√2/2
again
y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]
4.
Sin 30=8/x
½×x=8
x=8*2
x=16
again
cos 30= y/x
√3/2×16=y
y=8√3
5.
sin 60=7/x
x=7/[√3/2]
x=14/√3 or 14√3/3
again
cos 60=y/x
½×14√3/3=y
7√3/2=y
y=7√3/2
<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u>
<u>S</u><u>i</u><u>n</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>p</u><u>e</u><u>r</u><u>p</u><u>e</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u>/</u><u>h</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u>e</u>
<u>C</u><u>o</u><u>s</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>b</u><u>a</u><u>s</u><u>e</u><u>/</u><u>h</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u>e</u>
<u>T</u><u>a</u><u>n</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>p</u><u>e</u><u>r</u><u>p</u><u>e</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u> </u><u>/</u><u>b</u><u>a</u><u>s</u><u>e</u>
B. Dilation because it's changing size
Answer:
C. 28 = (2x - 1)(x)
Step-by-step explanation:
There is a rectangular swimming pool.
Width of swimming pool is x
Length is one less than twice the width
Area of the swimming pool is 28 sq ft.
To Find : Equation could be used to model the area of the swimming pool.
Solution:
Since we are given that Length is one less than twice the width.
And width is x (given)
So, length = 2x-1
Area of the swimming pool is 28 sq ft.
Now ,
Formula of area of rectangle : Length*Width
⇒28= (2x-1)(x)
So, equation used to model the area of the swimming pool: 28= (2x-1)(x)
Hence Option c is correct.