Answer:
LCM of 6 and 15 = 30
Step-by-step explanation:
LCM = 3 × 2 × 5 = 30
In case you were wondering, the GCD is 3.
Hope this helps!
Answer:
Step-by-step explanation:
Upper box in the diamond: Add the two numbers ⇒ (-2) + 3 = -1
Bottom box in the diamond : Multiply the two numbers ⇒ (-2) * 3 = -6
3) Upper box = (-6) + (-3) = (-9)
Bottom box = (-6) *(-3) = 18
4) Upper box = 1 +(-11) = -10
Bottom box = 1 *(-11) = -11
5) Upper box = 7+8 = 15
Bottom box = 7*8 = 56
Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

Hey use photo math is gonna help you a lot