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Westkost [7]
3 years ago
15

What is 320/25 in a mixed number

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0
The answer will be 12 4/5
320/25 the you simplify by 5
64/5 ➗ by 5
12 4/5
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Find the LCM of 6 and 15.
Taya2010 [7]

Answer:

LCM of 6 and 15 = 30

Step-by-step explanation:

LCM = 3 × 2 × 5 = 30

In case you were wondering, the GCD is 3.

Hope this helps!

8 0
3 years ago
Read 2 more answers
The first two diamonds are filled in, can you figure out how the numbers are related when
balu736 [363]

Answer:

Step-by-step explanation:

Upper box in the diamond: Add the two numbers  ⇒ (-2) + 3 = -1

Bottom box in the diamond : Multiply the two numbers ⇒ (-2) * 3 = -6

3) Upper box = (-6) +  (-3)  = (-9)

Bottom box = (-6) *(-3) = 18

4) Upper box  = 1 +(-11) = -10

 Bottom box = 1 *(-11) = -11

5) Upper box = 7+8 = 15

Bottom box = 7*8 = 56

7 0
2 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
94 1/4 divided by 7 1/4
Lerok [7]
The answer is 13 :)))
6 0
3 years ago
Read 2 more answers
Please help! show explanation please​
Rudiy27
Hey use photo math is gonna help you a lot
4 0
2 years ago
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