All categories

2 years ago

I don’t know how to solve it can someone help me?

Mathematics

1 answer:

bearhunter [10]2 years ago

6 0

Answer:

Step-by-step explanation:

Because the arcs HI and GJ are the same, that means that the segments HI and GJ are also the same. Therefore,

c + 20 = 2c and

20 = c

You might be interested in

If two sides of a triangle are 9cm and 15cm in length, which COULD be the measure of the third side?

MArishka [77]

The lemght could be 15 because a triangle has two long sides and one short one and the two are equivalent

5 0

3 years ago

Solve for x: 4 over 5 x + 4 over 3 = 2x x =

Naily [24]

Answer:

over 5 x + 4 over 3 = 2x

can't find x

Hi McDa:

Here's a couple hints. (I have no idea what you already understand. Please check out our posting guidelines.)

Express the Natural number 3 in Rational form 3/1.

Regarding the left-hand side above, have you learned the property that says we may multiply by the reciprocal of 3/1, instead of dividing by 3/1?

Step-by-step explanation: Incorrect? Let me know!

8 0

2 years ago

The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

5 0

3 years ago

Need help fast!!!!!!!!

Kamila [148]

C. 2/3; reduction
have a good day

4 0

3 years ago

Dilations Quick Check Geometry Connexus U4L5

olga2289 [7]

Just use quiz lit and it’ll give you all the answers you need for your answers. Ok. Ok. Keixhshshwiwie I rrjicicjrjwjwiwosodod.

8 0

2 years ago