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3 years ago

Solve for x:− 10x + 4 = − 7x − 14 −7x −14PLEASE HELP ME!

Mathematics

2 answers:

balandron [24]3 years ago

8 0

Just by using distributive property i got x=-8

Elodia [21]3 years ago

7 0

Step-by-step explanation:

-10x + 4 = -7x - 14 - 7x - 14

-10x + 4 = -14x - 28

4x = -32

x = -8.

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tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0$

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}$

$\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

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$\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}$ if x ≠ ±1

$(\frac{2}{1-x})^2=\frac{4+x}{1-x}$ [Squaring on both the sides of the equation]

$\frac{4}{(1-x)}=(4+x)$

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

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