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3 years ago

Suppose that f is a sine function ... look at the picture

Mathematics

1 answer:

Triss [41]3 years ago

8 0

Answer:

f(3π/4) = -π

A = π

b = 2

Step-by-step explanation:

Given that the function follows the form: f(x) = A sin(bx), then f(0) = 0. Given that the period is π, then at x = π/4 the function reaches a maimum, at x = π/2, f(x) = 0, and at x = 3π/4, f(x) reaches a minimum, which have to be π*(-1) = -π

Given the general equation: f(x) = A sin(bx), its period is calculated as:

period = 2π/b

which is equal to π, then:

2π/b = π

b = 2

Replacing x = π/4 into the equation of the function, we get:

A sin(2(π/4)) = π

A sin(π/2) = π

A = π

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soldi70 [24.7K]

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