Very technically, yes. But . . .
-- Its angles would be 0°, 0°, and 180° .
-- Its height and area would both be zero.
-- It would look like a line segment, because the two ' 6 ' legs
would have to be wide open in a straight line, and they would
lie right on top of the ' 12 ' leg ... that's the only way they could
reach between the ends of it.
Answer:
Answer: Mercury metal is poured into a graduated cylinder that holds exactly 22.5 mL. The mercury used to fill the cylinder weighs 306.0 g
Step-by-step explanation:
Answer:
And we can find this probability using the normal standard table with this difference:
Step-by-step explanation:
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
We are interested on this probability
And we can solve the problem using the z score formula given by:
Using this formula we got:
And we can find this probability using the normal standard table with this difference:
<h3>
Answer: 36.4 units (choice A)</h3>
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Explanation:
Let's use the distance formula to find the distance from D to E
Note: uppercase D refers to the point, while lowercase d is the distance from D to E.
The length of segment DE is roughly 10.198 units long.
----------------
Repeat for the distance from E to F.
Segment EF is roughly 11.1803 units long.
----------------
Repeat for the distance from F to D.
Unlike the others, this result is exact.
----------------
Add up the three segment lengths to get the perimeter
DE + EF + FD
10.198 + 11.1803 + 15
36.3783
The perimeter is approximately 36.3783 units which rounds to <u>36.4</u>
The answer has been confirmed with GeoGebra.
Answer:
The set A ∩ B contain {6, 12}
Step-by-step explanation:
Given : set A = {3, 6, 9, 12} and set B = {2, 4, 6, 8, 10, 12}
We have to find A ∩ B
Consider the given sets
Set A = {3, 6, 9, 12}
and set B = {2, 4, 6, 8, 10, 12}
Since, A ∩ B includes those elements that are both in set A and set B.
Thus, the common elements of A and B are 6 and 12
So , the set A ∩ B contain {6, 12}