Sum/difference:
Let
This means that
Now, assume that 
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get
if again we assume x to be rational, we have
But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
Answer:
(a-z)/z = m
Step-by-step explanation:
a = zm+z
Subtract z from each side
a-z = mz+z-z
a-z = mz
Divide by z
(a-z) /z = mz/z
(a-z)/z = m
Answer:
The point ”A“ is the point that corresponds to the last entry in the table.
Step-by-step explanation:
$0.60 cents would be the cost of 2 lbs
The three integers are: 12, 13, and 14
12+13=25
25+14=39
