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AfilCa [17]
3 years ago
12

If 3/4 of the class likes soda and 3/5 of those who like soda prefer Coke, what PERCENT of the whole class that likes Coke?

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

For soda =3/4

For coke= 3/5 X 3/4=9/20

Whole class is 1....

Therefore X% of 1 =9/20

Solving :

X/100 X 1 =9/20

X/100=9/20

20X =900

X= 900/20 = 45%

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Bobby wants to go on a school trip that will cost him $250. He comes up with an equation that represents how much he needs to sa
monitta
Yes, Bobby will have enough money if he saves for 9 weeks. You can find this through either substituting w for 9 in the equation, or solving the equation itself. 

Substituting:

25(9)+30
Substitute w for 9. 

225+30
Simplify. 

225+30=255
Solve. 

255 is greater than 250, so yes, he will have enough money saved. 


Solving the equation:

25w+30=250
Original Equation

25w=220
Subtract 30 from both sides. 

w=8.8
Divide both sides by 25. 

The number of weeks he needs is 8.8. When rounding it up, you get 9. 


4 0
3 years ago
WILL MARK YOUR ANSWER AS BRAINLIEST how do I do this
NeX [460]

By the definition of a rectangle, JML and KLM are right angles.

<h3>How to explain the information?</h3>

From the information given, JKLM is a rectangle based on the definition as the opposite sides are equal.

Also, JML and KLM will be 90° since they're right angles. The opposite sides of a rectangle are congruent and equal.

Learn more about rectangles on:

brainly.com/question/25292087

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3 0
2 years ago
A product is composed of four parts. In order for the product to function properly in a given situation, each of the parts must
svet-max [94.6K]

Answer:

P(working product) = .99*.99*.96*.96 = .0.903

Step-by-step explanation:

For the product to work, all four probabilities must come to pass, so that

P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)

where

P(Part-1) = 0.96

P(Part-2) = 0.96

P(Part-3) = 0.99

P(Part-4) = 0.99

As all parts are independent, so the formula is P(A∩B) = P(A)*P(B)

P (Working Product) =  P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)

P (Working Product) = 0.96*0.96*0.96*0.99*0.99

P(Working Product) = 0.903

3 0
3 years ago
alvaro pesa 13 kg menos que javier y 6 kg mas que maria si alvaro pesa 38 kg cuanto pesan javier y maria
Nataliya [291]

<span>Maria tiene 32 kg y javier tiene 51 kg
</span>
(google translate, bad spanish)
5 0
3 years ago
Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
3 years ago
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