Answer:
60%
Step-by-step explanation:
You can solve this problem by setting up a system of equations.
Let's say that the number of tickets bought by students in the first year is x, and the number bought by continuing students is y. From there, you can set it up like this:
0.4x+0.2y=160
x+y=500
Now, you can multiply the first equation by 5 on both sides to get:
2x+y=800
Subtracting the second equation from the first equation now yields:
x=300
y=200
Since 300 of the 500 tickets bought were from the first year students, and 300/500 is 0.6, 60% of the students who bought the ticket were first year students. Hope this helps!
Answer:
85.5
Step-by-step explanation:
5+((7*23)/2)
first you do 7*23
second you do 161/2
finally you do 80.5 + 5
Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130
has a pvalue of 0.9772
X = 110
has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
Answer:
![5\sqrt[4]{x}](https://tex.z-dn.net/?f=5%5Csqrt%5B4%5D%7Bx%7D)
or the fourth answer
Step-by-step explanation:
Apply the rule ![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
to rewrite the exponentiation as a radical.
![5\sqrt[4]{x^1}](https://tex.z-dn.net/?f=5%5Csqrt%5B4%5D%7Bx%5E1%7D)
Anything raised to 1 is the base itself.
Answer =
Plz mark me brainliest, hope this helps.
Answer:
1. m∠B=110°
2. 560 cm3
3. Numerical data
4. 2000 cm3
5. 50%
Step-by-step explanation:
1. The explanation of part 1 is given in the attachment.
2. Given dimensions : 10 cm, 8 cm, and 7 cm.
Let Length of cuboid =10 cm
breadth/width of cuboid =8 cm
height of cuboid = 7cm
Volume of cuboid = length *width* height
=( 10 *8*7) cm3
=(560) cm3
3. Age, Birth date and weight are the types/examples of "<u>Numerical Data"</u> because these all are describe in terms of numeric values.
4. 1 liter = 1000 cm3 or 1 cm3 = 0.001 liter
1.5 liters =(1.5*1000) cm3 = (15*100) =1500 cm3
1 dm3 =1000 cm3
0.35 dm3 = (0.35*1000) cm3 = (35*10) cm3 =350 cm3
Given expression: 1.5 litre + 0.35 dm3 + 150 cm3 = <u> </u> cm3
1500 cm3 + 350 cm3 +150 cm3 = <u>2000</u> cm3
5. If A=(1/2)B, then B : A = <u>50</u> %
Ratio: B : A
B : (1/2) B
1: (1/2)
50 % (The value of A is half of the value of B)
