Ask question

Ask question

All categories

2 years ago

15

There are 81 women teachers at Russell High. If 45% of the teachers in the school are women, how many teachers are there at Russ

ell High?

1 answer:

igor_vitrenko [27]2 years ago

4 0

Answer:

180 teachers

Step-by-step explanation:

In this case, we know the value corresponding to 45% of female teachers which is 81, therefore, to find the total it would be:

% teachers #teachers

45 81

100 x

we apply the rule of three:

x = 100 * 81/45

x = 180

which means that there are a total of 180 teachers at Russell High

You might be interested in

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$

Therefore the change in volume is estimated to be 17.20 $\rm{in^3}$

4 0

2 years ago

Please help! I don't get it cause the person that was teaching it had horrible handwriting ;-;

lions [1.4K]

Answer: power of a power

Step-by-step explanation:

in the expression (x^4)^9, 4 and 9 are powers. 9 is the power of x^4, so you have to multiply 4 by 9 to get x^36. this means it's a power of a power

3 0

3 years ago

I need help with these two

Zinaida [17]

1. Adding all the responses together, we get the total number of responses is 24. The number of people who chose a genre that wasn't mystery was 7 for science fiction, 6 for history, and 3 for biographies. This means we will have 3 fractions before reducing. 7/24, 6/24, and 3/24. 7/24 is in simplest form, but 6/24 and 3/24 can be reduced. 6/24 can be 3/12 and 1/4. 3/24 can be 1/8. The answer will be to circle 7/24, 6/24, 3/12, 1/4, 3/24, or 1/8.

2. Plot the points given, and mirror them for point B and C to form the figure. When connecting them, the resulting figure should look extremely similar to the picture given.

4 0

2 years ago

Aaron, Darren, Karen, Maren, and Sharon rode on a small train that has five cars that seat one person each. Maren sat in the las

Aleks04 [339]

Answer:

Sharon

Step-by-step explanation:

The given parameters are;

The number of persons that rode on the small train = 5

The number of cars in the train = 5

The position Maren sat = Last car

The position Aaron sat = Directly behind Sharon

The position Darren sat = In one of the cars in front of Aaron

The position of one of the members = Between Karen and Darren

The given seating arrangement is as follows;

Maren → Aaron → Sharon → Darren → Karen

Therefore, the person who sat in the middle car is Sharon.

7 0

2 years ago

Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

$=(2^5)^\frac{1}{5}$

$=2$

There is no extraneous solution.

3 0

2 years ago