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Veseljchak [2.6K]
3 years ago
9

Let f(x) =4x-1 and g(x) = 2x^2 + 3 (fg)(x) , f/g(x), g/f(x)

Mathematics
1 answer:
sveta [45]3 years ago
6 0
F(x) = 4x - 1
g(x) - 2x² + 3

<u>(f · g)(x)</u>
(f · g)(x) = (4x - 1)(2x² + 3)
(f · g)(x) = 4x(2x² + 3) - 1(2x² + 3)
(f · g)(x) = 4x(2x²) + 4x(3) - 1(2x²) - 1(3)
(f · g)(x) = 8x³ + 12x - 2x² - 3

<u>(f/g)(x)</u>
(f/g)(x) = <u>4x - 1</u>
             2x² + 3

<u>(g/f)(x)</u>
(g/f)(x) = <u>2x² + 3</u>
               4x - 1
(g/f)(x)= ¹/₂x + ¹/₈ + <u> 3¹/₈ </u>
                              4x - 1
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