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I am Lyosha [343]
3 years ago
12

Which ordered pairs in the form (x, y) are solutions to the equation

Mathematics
1 answer:
Levart [38]3 years ago
4 0
The answer is a and c
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What is the slope intercept form for a line that is parallel to y= 3x +2 and passes through (2,-4)
uysha [10]

Answer:

same

Step-by-step explanation:

5 0
4 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
jenyasd209 [6]
<h3>Answers:</h3><h3>There are four solutions and they are</h3>
  • \theta = 0
  • \theta = \pi
  • \theta = \frac{7\pi}{6} ... this says "7pi over 6"
  • \theta = \frac{11\pi}{6} ... this says "11pi over 6"

===========================================

Work Shown:

\sin(\theta)+1 = \cos(2\theta)\\\\\sin(\theta)+1 = 1-2\sin^2(\theta)\\\\\sin(\theta)+1-1+2\sin^2(\theta)=0\\\\2\sin^2(\theta)+\sin(\theta)=0\\\\\sin(\theta)(2\sin(\theta)+1)=0\\\\\sin(\theta)=0 \ \text{ or } \ 2\sin(\theta)+1=0\\\\

----------

Solving \sin(\theta)=0 leads to \theta=n\pi for any integer n.

----------

Solving 2\sin(\theta)+1=0 leads to...

2\sin(\theta)+1=0\\\\2\sin(\theta)=-1\\\\\sin(\theta)=-\frac{1}{2}\\\\\theta=\arcsin\left(-\frac{1}{2}\right) \ \text{ or } \ \theta=\pi-\arcsin\left(-\frac{1}{2}\right)\\\\\theta=\frac{11}{6}\pi+2\pi n \ \text{ or } \ \theta=\pi-\frac{11}{6}\pi+2\pi n\\\\\theta=\frac{11}{6}\pi+2\pi n \ \text{ or } \ \theta=\frac{-5}{6}\pi+2\pi n\\\\\theta=\frac{11}{6}\pi+2\pi n \ \text{ or } \ \theta=\frac{7}{6}\pi+2\pi n\\\\

-----------

The general solution set is

\{\theta=n*\pi, \theta=\frac{11}{6}\pi+2\pi n, \theta=\frac{7}{6}\pi+2\pi n\}

Again, n is any integer.

Let's look at a table of values where we plug in various integers for n. See the attached image below. Note the stuff in the highlighted yellow cells represents expressions that are between 0 and 2pi = 6.28

Therefore the four solutions are \{0, \pi, \frac{7\pi}{6}, \frac{11\pi}{6}\} after we plug the proper values of n into the expressions, to have things match what the table shows.

6 0
3 years ago
Please help, it’s due today.
hjlf

Answer:

https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php try this website, it shows a step by step solution, and is a calculator for your problem <3

Step-by-step explanation:

6 0
3 years ago
Make a the subject of the formula x²=a²-a²w²​
Gwar [14]

Answer:

a = ± \sqrt{\frac{x^2}{1-w} }

Step-by-step explanation:

Given

x² = a² - a²w ← factor out a² from each term on the right side

x² = a²(1 - w) ← divide both sides by (1 - w)

\frac{x^2}{1-w} = a² ( take the square root of both sides )

± \sqrt{\frac{x^2}{1-w} } = a

3 0
3 years ago
The world's population has grown at an average rate of 1.9 percent per year since 1945. There were approximately 4 billion peopl
kkurt [141]

Answer:  f(t) = 4000000000( 1 .019)^t

Step-by-step explanation:

Here, According to the question,  The population of the world is 4 billion (approx).

Again According to the question, The world's population has grown at an average rate of 1.9 percent per year since 1945.

Therefore, after 1975 the growth rate will remains same.

Thus, the population of the world after t years,

f(t) = 4000000000( 1+\frac{1.9}{100} )^t   (By the formula A = P(1+\frac{r}{100})^t )

⇒f(t) = 4000000000( 1.019 )^t

Where 1.019 is the growth rate and 4 billion is the initial population.


6 0
3 years ago
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