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raketka [301]
2 years ago
8

If angle PQR and angle RQS form a linear pair and angle PQR =5x+5 and angle RQS =11x-65 then angle PQR=?

Mathematics
1 answer:
Mama L [17]2 years ago
3 0

Answer:

m<PQR = 80°

Step-by-step explanation:

<u>Points to remember</u>

Sum angles in a linear pair is 180

<u>To find the value of x</u>

It is given that, angle PQR and angle RQS are linear pairs, and

m< PQR =5x+5 and m<RQS =11x-65

m<PQR + m<RQS = 180

5x + 5 + 11x - 65 = 180

16x -60 = 180

16x = 180 + 60

16x = 240

x = 15

<u>To find the value of angle PQR</u>

m<PQR = 5x + 5

 = 5*15 + 5

 = 75 + 5 = 80

Therefore m<PQR = 80°

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Help please asap just the answers​
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\underline \bold{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  }

\huge\underline{\sf{\red{Problem:}}}

7.) Detemine the value of \sf{ {3a}^{2}  -b.}

\huge\underline{\sf{\red{Given:}}}

\quad\quad\quad\quad\sf{a = 2}

\quad\quad\quad\quad\sf{b =  - 1}

\quad\quad\quad\quad\sf{c =  - 3}

\huge\underline{\sf{\red{Solution:}}}

\quad\quad\quad\quad\sf{⟶{3a}^{2}  - b}

\quad \quad \quad \quad   \sf{⟶{(3)( 2)}^{2}  -( - 1)}

\quad \quad \quad \quad   \sf{⟶3(4)-( - 1)}

\quad \quad \quad \quad   \sf{⟶12-( - 1)}

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\huge\underline{\sf{\red{Answer:}}}

\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}

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\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)}  - ( - 2)( - 3)}

\quad\quad\quad\quad\sf{⟶{( - 8)}  - ( 6)}

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\huge\underline{\sf{\red{Answer:}}}

\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}

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\sf{\red{✍︎ C.Rose❀}}

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Learn more about the volume of a rectangular prism here;

brainly.com/question/4016105

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