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raketka [301]
3 years ago
8

If angle PQR and angle RQS form a linear pair and angle PQR =5x+5 and angle RQS =11x-65 then angle PQR=?

Mathematics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

m<PQR = 80°

Step-by-step explanation:

<u>Points to remember</u>

Sum angles in a linear pair is 180

<u>To find the value of x</u>

It is given that, angle PQR and angle RQS are linear pairs, and

m< PQR =5x+5 and m<RQS =11x-65

m<PQR + m<RQS = 180

5x + 5 + 11x - 65 = 180

16x -60 = 180

16x = 180 + 60

16x = 240

x = 15

<u>To find the value of angle PQR</u>

m<PQR = 5x + 5

 = 5*15 + 5

 = 75 + 5 = 80

Therefore m<PQR = 80°

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The true statement is:

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Third one:

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In this case, the quadratic function is:

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Then the y-value of the vertex is:

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8 0
2 years ago
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Why?

Since second coordinates of R and S are the same so we can just count the length by adding first coordinate of R and first coordinate of S= |-3|+4=7

Since first coordinates of R is the same as first coordinate of T so we can just count  the length  by adding second coordinates of S and T=5+|-2|=7

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3 years ago
There is money to send four of nine city council members to a conference in Honolulu. All want to go, so they decide to choose t
FrozenT [24]

Answer:

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