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3 years ago

8

In the world’s coldest freezer, sodium gas was cooled to a temperature of 78.5°C below zero and then cooled 194.65°C more. What

was the new temperature of the sodium gas?

2 answers:

andrey2020 [161]3 years ago

8 0

Answer:

–273.15°C

Step-by-step explanation:

masya89 [10]3 years ago

5 0

Answer:

-202.5 celsius

Step-by-step explanation:

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LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )

Dimas [21]

143 / 6x+12 = 132 / 72
143 / 6x+12 = 11 / 6

crossmultiply:
66x + 132 = 858
66x = 726
x = 11

8 0

2 years ago

Read 2 more answers

A plant 3 inches tall grows an average of 0.5 inches each month. Which equation models the heigh h after x months

anzhelika [568]

Answer:H = 3 + 0.5x

Step-by-step explanation:

This would be H = 3 + 0.5x

5 0

3 years ago

5m<72; m=15. Help me help my son I'm confused

VARVARA [1.3K]

Answer:

The inequality is incorrect.

Step-by-step explanation:

Plugging in the value for m (15) and solving, we find that the inequality cannot be correct, as 75 is greater than, NOT less than 72.

4 0

3 years ago

A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L

Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider $\Delta ABC$ as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

$\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}$

From the given data, $L=15\:ft=AC$ , $y=9\:ft=AB$ and $x=BC$

Substituting the values,

$\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}$

$\therefore 81+x^{2}=225$

$\therefore x^{2}=225-81$

$\therefore x^{2}=144$

$\therefore \sqrt{x^{2}}=\sqrt{144}$

$\therefore x=\pm 12$

Since length can never be negative, so $x= 12$ .

Now to calculate $\dfrac{dy}{dt}$ again consider following equation,

$\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}$

Differentiate both sides of the equation with respect to t,

$\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)$

Applying sum rule of derivative,

$\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)$

$\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)$

Applying power rule of derivative,

$2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0$

Simplifying,

$y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0$

Substituting the values,

$9\dfrac{dy}{dt}+12\times1.5=0$

$9\dfrac{dy}{dt}+18=0$

Subtracting both sides by 18,

$9\dfrac{dy}{dt}=-18$

Dividing both sides by 9,

$\dfrac{dy}{dt}= - 2$

Here, negative indicates that the ladder is sliding in downward direction.

$\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}$

7 0

3 years ago

Leya [2.2K]

Answer:

Dan's car depreciated by 54% after 6 years.

Step-by-step explanation:

Price of a depreciating asset:

The price of a depreciating asset after t years is given by:

$P(t) = P(0)(1-r)^{t}$

In which P(0) is the initial price and r is the decrease rate, as a decimal.

Dan's car depreciates at a rate of 12% per year.

This means that $r = 0.12$ , so

$P(t) = P(0)(1-r)^{t}$

$P(t) = P(0)(1-0.12)^{t}$

$P(t) = P(0)(0.88)^{t}$

By what percentage has Dan's car depreciated after 6 years?

Relative to the initial value, the value after 6 years is given by:

$P(6) = P(0)(0.88)^6 = 0.46P(0)$

The value after 6 years if 0.44 of the initial value, that is, there was a depreciation of 100 - 46 = 54%.

Dan's car depreciated by 54% after 6 years.

3 0

3 years ago