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Nookie1986 [14]
3 years ago
9

Evaluate the expression if : a = 5, b = 3 6a – 4b

Mathematics
1 answer:
Allushta [10]3 years ago
7 0
6(5)-4(3)
30-12
Answer: 18
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I do not know what to put and this was due yesterday
atroni [7]

Answer:

Your answer will be x=2

Step-by-step explanation:

Five plus 6 times a number is equal to 21 minus 2 times the number

Your equation is this:

5+6x=21-2x

Subtract 6x from both sides

5+6x-6x=21-2x-6x

5=21-8x

subtract 21 on both sides

5-21=21-21-8x

-16=-8x    Divide -8 on both sides

2=x

Hope this helps :)

8 0
2 years ago
Kiran’s backpack weighs 3 pounds less than Clare’s backpack. Clare’s backpack weighs 14 pounds. How much does Kiran’s backpack w
Nina [5.8K]
14-3=11, The answer is 11
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2 years ago
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What is 66% of $444? (Round to the nearest whole number)
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$444-66%= $150.96= $151
8 0
2 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

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2 years ago
Which statement best describes tuition
Kitty [74]
 Tuition is the price of attending classes at a school. Your welcome. 
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3 years ago
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