The length of side A is 8.8 cm and length of side B is 4.4 cm and length of side C is 12.8 cm
<em><u>Solution:</u></em>
Let the length of side A be "a"
Let the length of side B be "b"
Let the length of side C be "c"
<em><u>Side A of a triangle is twice the length of side B</u></em>
a = 2b
![b = \frac{a}{2} --------- eqn 1](https://tex.z-dn.net/?f=b%20%3D%20%5Cfrac%7Ba%7D%7B2%7D%20---------%20eqn%201)
<em><u>Side C is 4 cm longer then side A</u></em>
c = 4 + a ------------- eqn 2
The perimeter is 26 cm
<em><u>The perimeter of triangle is given by formula:</u></em>
Perimeter = a + b + c
Where, "a", "b", "c" are the length of sides of triangle
Therefore,
26 = a + b + c
<em><u>Substitute eqn 1 and eqn 2 in above</u></em>
![26 = a + \frac{a}{2} + 4 + a\\\\26 = \frac{2a + a + 8+2a}{2}\\\\26 \times 2 = 5a +8\\\\5a + 8 = 52\\\\5a = 52 - 8\\\\5a = 44\\\\a = 8.8](https://tex.z-dn.net/?f=26%20%3D%20a%20%2B%20%5Cfrac%7Ba%7D%7B2%7D%20%2B%204%20%2B%20a%5C%5C%5C%5C26%20%3D%20%5Cfrac%7B2a%20%2B%20a%20%2B%208%2B2a%7D%7B2%7D%5C%5C%5C%5C26%20%5Ctimes%202%20%3D%205a%20%2B8%5C%5C%5C%5C5a%20%2B%208%20%3D%2052%5C%5C%5C%5C5a%20%3D%2052%20-%208%5C%5C%5C%5C5a%20%3D%2044%5C%5C%5C%5Ca%20%3D%208.8)
<em><u>Substitute a = 8.8 in eqn 1</u></em>
![b = \frac{8.8}{2}](https://tex.z-dn.net/?f=b%20%3D%20%5Cfrac%7B8.8%7D%7B2%7D)
b = 4.4
<em><u>Substitute a = 8.8 in eqn 3</u></em>
c = 4 + 8.8
c = 12.8
Thus length of side A is 8.8 cm and length of side B is 4.4 cm and length of side C is 12.8 cm