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Alchen [17]
3 years ago
13

In class of 40 students, 19 play tennis, 20 play netball and 8 play both. A student is randomly chosen from the class. Determine

the probability that the student plays one and only one of those sports ?
Mathematics
2 answers:
Lerok [7]3 years ago
8 0

Answer:

4/5 or 0.8 or 80%

Step-by-step explanation:

ollegr [7]3 years ago
8 0
32/40 simplifies to 4/5
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56

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(3+2i)(3-2i) whats the answer
Ludmilka [50]

Answer:

13 is the answer.

Step-by-step explanation:

7 0
3 years ago
Can yall help me I really need this done. <br> Thank you much love
Ulleksa [173]

Let's use the furthest left point on the triangle to figure out the translation.

Blue triangle = (-5,1)

Black triangle = (-3,-1)

To get from -5 to -3 we moved the triangle 2 units to the right, which means that we added 2.

To get from 1 to -1, we moved the triangle 2 units down, which means we subtracted 2.

Rule: {2, -2}

Hope this helps!

5 0
3 years ago
30 + a = 40<br> 40 + b = 30<br> c - 3 = 8<br> d - 3 = 8<br> plz answer.
sesenic [268]

Answer:

A= 10

B= -10

C and D both = 11

4 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
4 years ago
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