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sladkih [1.3K]
3 years ago
7

Sara owns an exotic pet store. She wants to make sure she has more than a pound of food for every 15 lizards she has in the stor

e. If she currently has 4.25 pounds of food, how many lizards can she have in the store? Which inequality can be used to solve the problem? Solve the inequality. How can you interpret the solution?
Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

1.x/15 < 4.25

2. she can have a maximum of 63 lizards.

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago
3 0

Answer:

A 1st B 3rd

Step-by-step explanation:

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Reptile [31]

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3 years ago
11/6358 long agurithum
miss Akunina [59]

Answer:

Least common multiple:

lcm (578; 11) = 6,358 = 2 × 11 × 172;

Numbers have no common prime factors: 6,358 = 578 × 11.

Step-by-step explanation:

Approach 1. Integer numbers prime factorization:

578 = 2 × 172;

11 is a prime number, it cannot be broken down to other prime factors;

Multiply all the prime factors, by the largest exponents.

Least common multiple:

lcm (578; 11) = 2 × 11 × 172;

lcm (578; 11) = 2 × 11 × 172 = 6,358

Numbers have no common prime factors: 6,358 = 578 × 11.

Integer numbers prime factorization

Approach 2. Euclid's algorithm:

Calculate the greatest (highest) common factor (divisor), gcf, hcf, gcd:

Step 1. Divide the larger number by the smaller one:

578 ÷ 11 = 52 + 6; Step 2. Divide the smaller number by the above operation's remainder:

11 ÷ 6 = 1 + 5; Step 3. Divide the remainder from the step 1 by the remainder from the step 2:

6 ÷ 5 = 1 + 1; Step 4. Divide the remainder from the step 2 by the remainder from the step 3:

5 ÷ 1 = 5 + 0; At this step, the remainder is zero, so we stop:

1 is the number we were looking for, the last remainder that is not zero.

This is the greatest common factor (divisor).

Least common multiple, formula:

lcm (a; b) = (a × b) / gcf, hcf, gcd (a; b);

lcm (578; 11) =

(578 × 11) / gcf, hcf, gcd (578; 11) =

6,358 / 1 =

6,358;

lcm (578; 11) = 6,358 = 2 × 11 × 172;

8 0
3 years ago
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