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Arada [10]
3 years ago
5

le" class="latex-formula">
Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

x²-9=x²-3²=(x+3)(x-3)

Step-by-step explanation:

use formula

a²-b²=(a+b)(a-b)

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Can someone please help me with this geometry question
goldenfox [79]

Answer:

A. q = 39

Step-by-step explanation:

Since the lines are parallel, their sides will be proportional,

So,

Taking their proportion

=> \frac{60}{40} = \frac{q}{26}

Cross Multiplying

q × 40 = 26 × 60

q = \frac{1560}{40}

q = 39

7 0
3 years ago
21. what are the excluded values of the function? y= 5/6x-72
tatiyna

you have to calculate the SID number and then take it upon yourself and divided X it's actual number and then there's a chance and the answer would be c.72

4 0
3 years ago
The shapes in this question are drawn on a centimetre grid.
xenn [34]

Answer:

A. 12 centimeters B. 4 centimeters C. 20 centimeters

Step-by-step explanation:

To find area you need to do the Height time the Length.

For A it is 3x4

For B it is 4x1

And for C it is 4x5

You get this equation by multiplying the amount of squares that the Height and Length measured!

Hope this helped!

:DD

8 0
3 years ago
Read 2 more answers
Which ordered pair is the solution to the system of equation
Neporo4naja [7]

Hello,

Please, see the attached file.

Thanks

3 0
3 years ago
Please help I will give Brainliest please!
WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
5 0
2 years ago
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