All categories

4 years ago

What are the steps used to solve a one- variable equation

Mathematics

1 answer:

Arlecino [84]4 years ago

3 0

Step 1: Simplify each side, if needed.

Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.

Step 3: Use Mult./Div. ...

Step 4: Check your answer.

You might be interested in

Let f(x) = 1/x. Find a number b so that the average rate of change of f on the interval

Bezzdna [24]

Answer:

huh try multiplying

Step-by-step explanation:

6 0

4 years ago

What is the length of the segment connecting the points A(1,3) and B(6,5)?

Natalija [7]

Answer:

The answer is

<h2> $\sqrt{29} \: \: \: or \: \: \:5.38 \: \: \: units$ </h2>

Step-by-step explanation:

The length of the segment connecting two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A(1,3) and B(6,5)

The length is

$|AB| = \sqrt{ ({1 - 6})^{2} + ({3 - 5})^{2} } \\ = \sqrt{ ({ - 5})^{2} + ( { - 2})^{2} } \\ = \sqrt{25 + 4} \\ = \sqrt{29}$

We have the final answer as

$\sqrt{29} \: \: \: or \: \: \:5.38 \: \: \: units$

Hope this helps you

3 0

3 years ago

Write an explicit formula for an,the Nth term of the sequence 4,12,36

Rudik [331]

Answer:

$3^{n}+3^{n-1}$

Step-by-step explanation:

Since the sequence is geometric (it multiplies the previous number each time). The nth term sequence would be $x^n + yn$

Because the sequence multiplies by 3 each time, The base number in that equation would be $3^n +yn$ .

So $3^n$ of the equation would be:
$3, 9, 27$ .

Compare the 2 equations:
4, 12, 36

3, 9 ,27

The difference between the 2 equations is: 1, 3, 9 which itself is a geometric sequence so the nth term of this new equation is: $3^{n-1}$ .

Combine these 2 equations together and you get:

$3^{n}+3^{n-1}$ .

6 0

2 years ago

1 (15 Points]. Prove the following statement: is divisible by 3 if only if it is a sum of three consecutive integers. be ddvisbk

Alinara [238K]

Answer:

<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.

Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:

n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).

So, n can be written as 3 times another integer, thus n is divisible by 3.

<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.

Assume that n is divisible by 3. The above proof suggest that we write it as

n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).

As k, k+1, k+2 are three consecutive integers, we have completed our goal.

Step-by-step explanation:

4 0

3 years ago

How many solutions can be found for the linear equation <br><br> 3(x/2 + 5 ) - 6 = ( 9x + 18 ) / 3

I am Lyosha [343]

answer: it would be one solution, becasue the variables are different and the constants dont matter, since the variables are different

5 0

3 years ago