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daser333 [38]
3 years ago
12

Solve 3x - 4 ≤ 2 or 2x + 11 ≥ -1

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0
1.) 3x -4 <_ 2
Add 4 to both sides.
-4 + 4 = 0
2 + 4 = 6
3x <_ 6
Divide both sides by 3.
3x / 3 = x
6 / 3 = 2
x <_ 2 is your answer for the first inequality.

2.) 2x + 11 _> -1
Subtract 11 from both sides.
11 - 11 = 0
-1 -1 = -2
2x _> -12
Divide both sides by 2.
2x / 2 = x
-12 / 2 = -6

x _> -6 is your answer for the second inequality.

I hope this helps!
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