500/4= 125
she has written 125 words and needs to write 375 more
A=49.44
B=232.91
C=-283.29
(49.44-232.91)+(-283.29)=-466.76
-283-(232.91+49.44)=-565.35
Answer:
6
Step-by-step explanation:
I used the formula d=√((x_2-x_1)²+(y_2-y_1)²), plugged in the numbers and solved and got 6 units.
Answer:
Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Step-by-step explanation:
We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.
<em>Let X = incomes for the industry</em>
So, X ~ N(
)
Now, the z score probability distribution is given by;
Z =
~ N(0,1)
where,
= mean income of firms in the industry = 95 million dollars
= standard deviation = 5 million dollars
So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)
P(X < 100) = P(
<
) = P(Z < 1) = 0.8413 {using z table]
Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.