In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
Answer:
50.27 or 16pi
Step-by-step explanation:
Just multiply the diameter by pi
What’s the question?
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Answer:
c=sqrt21
Step-by-step explanation:
angle c is the angle between a and b, so use the cos law
c^2=a^2+b^2-2*a*b*cosC
c^2= 16+25-2*4*5*1/2
c^2=21
c=sqrt21
Answer:
Step-by-step explanation:
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