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3 years ago

14

Which of the following segments is a radius of circle O?

2 answers:

Harlamova29_29 [7]3 years ago

8 0

I think it's RO if it's circle O

enyata [817]3 years ago

6 0

Answer: B. $\overline{RO}$

Step-by-step explanation:

We know that the radius of a circle is a line segment which starts from the center of the circle and ends to any point on the circle.

From the given figure , it can be seen that there are three line segments in the circle which starts from center to a point on circle .

Thus, The radius of the circle with center O= $\overline{AO},\ \overline{RO},\ \overline{SO}$

From the given options , line segment $\overline{RO}$ is a radius of circle O.

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koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

Substituting this into the other ODE gives

$-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0$

Since $x(t)=-\dfrac14y'(t)$ , it follows that $x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16$ . The ODE in $y$ has characteristic equation

$r^2-16=0$

with roots $r=\pm4$ , admitting the characteristic solution

$y_c=C_1e^{4t}+C_2e^{-4t}$

From the initial conditions we get

$y(0)=5\implies 5=C_1+C_2$

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$\implies C_1=\dfrac12,C_2=\dfrac92$

So we have

$\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}$

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Given the line -9x-6y=18. Find the slope

SashulF [63]

Answer:

slope = - $\frac{3}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

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Add 9x to both sides

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y = - $\frac{3}{2}$ x - 3 ← in slope- intercept form

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3 years ago

Determine whether the ffunction X/(x^2-1) is odd even or neither

djyliett [7]

equation is:

$f(x) = \frac{x}{ {x}^{2} - 1 }$

so if its even f(-x) should be equal to f(x)

that means

$f( - x) = \frac{ - x}{ {( - x)}^{2} - 1} \\ \\ f( - x) = - \frac{ x}{ {x}^{2} - 1}$

so f(x) is not equal to f(-x) so its not even

If its odd than f(-x) should be equal to -f(x)

$- f(x) = - ( \frac{ x}{ { x}^{2} - 1 } ) \\ - f(x) = - \frac{ x}{ {x}^{2} - 1 }$

so as we can see f(-x)= - f(x)

so the function is odd

Ans:function is odd and not even

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3 years ago