(3,51)(5,59)
slope = (59 - 51) / (5 - 3) = 8/2 = 4
y = mx + b
slope(m) = 4
(3,51)...x = 3 and y = 51
sub and find b, the y int
51 = 4(3) + b
51 = 12 + b
51 - 12 = b
39 = b
so ur equation is : y = 4x + 39...but u need it in standard form
y = 4x + 39
-4x + y = 39
4x - y = -39 <==== this is ur equation...x = number of hrs and y = total velocity
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ur x axis is the number of hrs
ur y axis is total velocity in km
y = 4x + 39......slope = 4.....y int = (0,39)....x int is (- 9.75,0) or -9 3/4 for graphing purposes)....so start at (-9.75,0)...and since the slope is 4, go up 4 and to the right 1....plot that...then up 4 and to the right 1...plot that...u will cross the y axis at (0,39)....and just connect ur plotted points and u have ur line......or what u can do since it is asking for the first 6 hrs....sub in 1 for x and solve for y....then sub in 2 for x and solve for y...keep doing this up till 6 and u will have ur line up till 6 hrs
V= 3 x 4^2 x 12
v= 576cm^3
Number 5a. is 26.78 and 5b. is 8.5
If a student tells me that an argument that has a false hypothesis cannot be valid, I would reply that we need to look carefully at the meaning of validity in the context of logic. In everyday speech, we tend to use “valid” to mean the same thing as “true” or “accurate.” In logic, this is not the way the term is used.
