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Tamiku [17]
2 years ago
11

PLSSSS Plsssss help quick

Mathematics
1 answer:
Neporo4naja [7]2 years ago
5 0

Answer:

(x, y) (1,5.5) , (2,5.75) (3,5.83) (4,5.875) (5,5.9)

Step-by-step explanation:

The x values lie on the horizontal line and the y values lie on the vertical line.

In order to find the value of y you must substitute the value of x in the equation given and you must plot you graph using the answers you got which I wrote for you.

NOTE:if there's anything you don't understand let me know.

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A jewelry designer is making a pendant. The pendant will be a circular dis (center O) with a circular hold cut out of it, as sho
antoniya [11.8K]

Answer:

2884.8 millimeters squared

Step-by-step explanation:

Given:

The radius of the disc is 35 millimeters, so the area of it is:

πr^{2} = 3.14*35^{2} = 3846.5

Then, we find out the area of the circular hold cut out of the bigger one, its radius is a haft of the radius of the bigger circle = 35/2 = 17.5

πr^{2} = 3.14*17.5^{2} =961.6

=>  the area of the pendant = 3846.5  - 961.6  =2884.8 millimeters squared

6 0
3 years ago
Hlo sir i am laavanya how are you​
Monica [59]

Answer:

thanks for free point Mark me as brain list

6 0
3 years ago
Read 2 more answers
What is the answer to this question!?
vladimir2022 [97]
 In your equation m=1
5 0
3 years ago
jar contains 51 coins which are either quarters or nickels. total value of jar is 5.15. how many of each type of coin do they ha
docker41 [41]
I believe there are 20 quarters and 3 nickels.....

Total value of the jar is $5.15.....

Quarters are worth 25 cents
And nickels are worth 5 cents.

First you know that there are 4 quarters in a dollar.
 You have 5 dollars so you do 4 x 5 = 20

So five dollars ($5.00) is 20 quarters.
And you still have 15 cents left.

Because quarters are 25 cents the rest are nickels.

Nickels are worth 5 cents so you'd do 5 x 3 = 15.

15 cents!

Add all this together and get $5.15.

So your answer is 

There are 20 quarters and 3 nickels in the jar.

 
8 0
3 years ago
NEED HELP !!!!!! READDD THE QUESTION THERE ARE TWO PARTS
mel-nik [20]

We have to find horizontal component of Mayosons velocity.

#a

\\ \tt\bull\leadsto V_x=vsin\theta

\\ \tt\bull\leadsto V_x=2.5sin36

\\ \tt\bull\leadsto V_x=2.5(0.58)

\\ \tt\bull\leadsto V_x=1.45m/s

#b

Here 2 vectors A=8 and B=2.5

\\ \tt\bull\leadsto \overrightarrow{R}

\\ \tt\bull\leadsto \sqrt{A^2+B^2+2ABcos\Theta}

\\ \tt\bull\leadsto \sqrt{8^2+2.5^2+2(8)(2.5)cos36}

\\ \tt\bull\leadsto \sqrt{64+6.25+40(0.8)}

\\ \tt\bull\leadsto \sqrt{70.25+32}

\\ \tt\bull\leadsto \sqrt{102.25}

\\ \tt\bull\leadsto 10.15m/s

3 0
3 years ago
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