Given a polynomial
and a point
, we have that

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

To fix the correct value for a, we impose
:

And so we must impose

So, the function we're looking for is

............ ........... .
Answer: Quedarían nueve
Step-by-step explanation:
on a horizontal number line . numbers to the left are less than numbers to the right .. numbers to the right are less than numbers to the left