Question

What is the sign of 3 x y 3xy3, x, y when x > 0 x>0x, is greater than, 0 and y < 0 y<0

Answer 1

Answer:

The sign is negative

Step-by-step explanation:

Given

$Expression = 3xy$

$x > 0$

$y$

Required

Determine the sign

The expression can be split into 3 factors

$(3) (x) (y)$

If x > 0 then x is positive and If y < 0 then y is negative

So, the expression becomes:

$(+3) (+x) (-y)$

Leave only signs

$(+) (+) (-)$

$+ * + = -$

So, we have:

$(+*+) (-)$

$(+) (-)$

$+ * - = -$

So, we have:

$(+) (-) = -$

Hence, the sign of the expression is negative

Take for instance;

$x = 2$

$y = -4$

The expression would be:

$3 *2 * - 4 =-24$ -- negative