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AURORKA [14]
2 years ago
5

A water cup in the shape of a cone has a height of 4 inches and a maximum diameter of 3 inches. What is the volume of the water

in the cup, to the nearest tenth of a cubic inch, when the cup is filled to half its height?
Mathematics
1 answer:
Debora [2.8K]2 years ago
3 0
The diameter of half the cone is equal to half of the given diameter and its height is also half the given height. 
                                   V = 1/3(πr²)(h)
d = 1.5 inches, r = 0.75 inches
h = 2 inches

Substituting,
                                   V = 1/3(π)(0.75 in)²(2 in)
                                          V = 1.178 in³
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Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te
motikmotik

Given:

There are given that the cos function:

cos210^{\circ}=-\frac{\sqrt{3}}{2}

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}

Then,

Put the value of cos210 degrees into the above function:

So,

\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}

Final answer:

Hence, the value of the cos(105) is shown below:

cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}

4 0
1 year ago
On a coordinate plane, a line has points (negative 2, negative 4) and (4, 2). Point P is at (0, 4). Which points lie on the line
NikAS [45]

Answer:

the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

Step-by-step explanation:

Given that a line passes through two points

A(-2, -4) and B(4, 2)

Another point P(0, 4)

To find:

Which points lie on the line that passes through P and is parallel to line AB ?

Solution:

First of all, let us the find the equation of the line which is parallel to AB and passes through point P.

Parallel lines have the same slope.

Slope of a line is given as:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{2-(-4)}{4-(-2)} = 1

Now, using slope intercept form (y = mx+c) of a line, we can write the equation of line parallel to AB:

y =(1)x+c \Rightarrow y = x+c

Now, putting the point P(0,4) to find c:

4 = 0 +c \Rightarrow c = 4

So, the equation is \bold{y=x+4}

So, the coordinates given in the options which have value of y coordinate equal to 4 greater than x coordinate will be true.

So, the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

8 0
3 years ago
Read 2 more answers
IF ANSWERED CORRECTLY WILL GIVE BRAINLIEST BUT IF YOU GIVE ME PDFS OR LINKS I WILL REPORT YOU
Alchen [17]

Answer:

Defending the inference and challenge

Step-by-step explanation:

The inference is correct no one chosen math. Most of them choose english, few of them choose history, and only two choose science.

There are 1000 7th grader, since they did not ask them what was their favorite subject. They could of had 65% for math, 25% for english, 5% for science and history. We do not know.

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4 0
3 years ago
Need help ASAP Tysm! :))
Mrrafil [7]

Answer:

The answer is -86

Step-by-step explanation:

-7 squared is 49

49 × 2 = 98

12-98= -86

4 0
3 years ago
laws of Sines with find the angle. Find each measurement indicated. Round your answers to the nearest tenth. Show your work plea
Gwar [14]

Answer:

4. Z ≈ 46.1°

5. T ≈ 45.2°

6. F ≈ 15.0°

Step-by-step explanation:

4.

We need to use the Law of Sines, which states that for a triangle with legnths a, b, and c and angles A, B, and C:

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Here, we can say that ZY = a = 30, X = A = 110, XY = b = 23, and Z = B. Plug these in to find Z:

\frac{a}{sinA} =\frac{b}{sinB}

\frac{30}{sin(110)} =\frac{23}{sinZ}

Solve for Z:

Z ≈ 46.1°

5.

Use the Law of Sines as above.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{26}{sin(76)} =\frac{19}{sinT}

Solve for T:

T ≈ 45.2°

6.

Again, use the Law of Sines as before.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{29}{sin(137)} =\frac{11}{sinF}

Solve for F:

F ≈ 15.0°

6 0
3 years ago
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