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scoundrel [369]
3 years ago
13

30/10 what is the answer

Mathematics
1 answer:
vekshin13 years ago
7 0
The answer is 3

hope this helps
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If GF is a midsegment of CDE, find CD.<br><br> A. 3.4<br><br>B. 6.8 <br><br>C. 13.6 <br><br>D. 14
bogdanovich [222]

Answer:

C


Step-by-step explanation:

Triangle CGF and triangle CED are similar. Hence, the ratio of their corresponding sides are equal. Thus we can write:

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}

<em>We can now cross multiply and solve for CD:</em>

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}

Since GF is a midsegment of CDE, CD is double of CF. So we can write:

CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0

<em>By using quadratic formula \frac{-b+-\sqrt{b^2-4ac} }{2a} and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:</em>

\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2


<em>Since the expression for CD is \frac{15x^2+16x+3.2}{2x+3} , we plug in x=2 into this expression to find value of CD:</em>

\frac{15(2)^2+16(2)+3.2}{2(2)+3}=13.6

The correct answer is C

6 0
3 years ago
Read 2 more answers
Jamaal thinks 19 can be divided by 6. Natalie does not think that 19 can be divided by 6
Paha777 [63]

Answer:

Natalie is correct

Step-by-step explanation:

6 does not go into 19 because there's a remainder of 1.

8 0
3 years ago
Read 2 more answers
Pre-algebra book 12.3.4 page 468
Olin [163]
What’s the question? i can help but uhh what’s the question
8 0
3 years ago
How many zeros are significant figures in a measured mass of 0.010010 g?
tekilochka [14]
Answer: 3

The first two zeros are not sig figs, but the next three zeros are sig figs
4 0
3 years ago
Determine if the following set of ordered pairs represents a quadratic function. Explain.
Digiron [165]

Answer:

Option D

Step-by-step explanation:

Given

(5, 7), (7, 11). (9, 14). (11, 18)

Required

Determine if the function is quadratic

(5, 7), (7, 11). (9, 14). (11, 18)

Start by representing the function as an x-y table

x:-  5 || 7 || 9 || 11

y:-  7 ||  11 || 14 || 18

Next; Calculate the difference between the values of y

Difference: 11 - 7 = 4

Difference: 14 - 11 = 3

Difference: 18 - 4 = 4

<em>The resulting difference are: 4 || 3 || 4</em>

Next; Calculate the difference between the difference of values of y

Difference = 3 - 4 = -1

Difference = 4 - 3 = 1

<em>The resulting difference are: -1 || 1</em>

<em>For the function to be quadratic, the above difference must be the same and since they are not, then the function does not represent a quadratic function.</em>

<em>Option D answers the question</em>

5 0
4 years ago
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