Using the shell method, the volume integral would be

That is, each shell has a radius of <em>x</em> (the distance from a given <em>x</em> in the interval [0, 2] to the axis of revolution, <em>x</em> = 0) and a height equal to the difference between the boundary curves <em>y</em> = <em>x</em> ⁸ and <em>y</em> = 256. Each shell contributes an infinitesimal volume of 2<em>π</em> (radius) (height) (thickness), so the total volume of the overall solid would be obtained by integrating over [0, 2].
The volume itself would be

Using the disk method, the integral for volume would be
![\displaystyle \pi \int_0^{256} \left(\sqrt[8]{y}\right)^2\,\mathrm dy = \pi \int_0^{256} \sqrt[4]{y}\,\mathrm dy](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cpi%20%5Cint_0%5E%7B256%7D%20%5Cleft%28%5Csqrt%5B8%5D%7By%7D%5Cright%29%5E2%5C%2C%5Cmathrm%20dy%20%3D%20%5Cpi%20%5Cint_0%5E%7B256%7D%20%5Csqrt%5B4%5D%7By%7D%5C%2C%5Cmathrm%20dy)
where each disk would have a radius of <em>x</em> = ⁸√<em>y</em> (which comes from solving <em>y</em> = <em>x</em> ⁸ for <em>x</em>) and an infinitesimal height, such that each disk contributes an infinitesimal volume of <em>π</em> (radius)² (height). You would end up with the same volume, 4096<em>π</em>/5.
Seven millon two hundred thirty thousand and fourteen
Answer:
Step-by-step explanation:
Steps Property
x(1 + y) + y(2 + x) Given
x + xy + 2y + xy Distributive property
x + xy + xy + 2y Commutative property of addition
[a + b = b + a]
x + (xy + xy) + 2y Associative property of addition
[(a + b) + c = a + (b + c)]
x + 2xy + 2y Combine like terms