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Pie
2 years ago
15

a shopkeeper bought two radios for Rs 6000.He sold one of them at a profit of 20% and the other at a loss of 10%.If he gained 2%

on his total outlay,at what price did he buy each radio?​
Mathematics
1 answer:
Naya [18.7K]2 years ago
7 0

Answer:

Rs1800

Step-by-step explanation:

20%*6000=1200

3000-1200=1800

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If a caterer charges a fixed cost for preparing a dinner plus an additional cost for each person served. You know that the cost
lozanna [386]
x+100y=750 \\ x+150y=1050 \\ 50y=300 \\ y=6 \\ x=750-600=150
The fixed cost is $150, while the per-student cost is $6.
3 0
3 years ago
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I went to the grocery store with $50. I purchased two gallons of milk for $3 each, a loaf of bread for $2, and three dozen of eg
Fofino [41]

Answer:

The answer to your question is $36

Step-by-step explanation:

Data

Total money = $50

2 gallons of milk = $3

a loaf of bread = $2

a dozen of eggs = $3

Write an equation to solve this problem

Cost of 2 gallons of milk + a loaf of bread + 3 dozens of eggs + remainder = total cost

Substitution

                          $3 + $2 + 3($3) + remainder = $50

Simplification

                          3 +  2 + 9 + remainder = 50

                          remainder = 50 - 3 - 2 - 9

result

                         remainder = $36                      

4 0
3 years ago
What is the image of (8,7) after a reflection over the line y=-x?
4vir4ik [10]

Answer:

(-7,-8)

Step-by-step explanation:

The original point is (8,7)

To reflect it, just switch their places and change their signs.

So, (-7,-8)

8 0
3 years ago
2/3x - 21/4 = 27/4 x=
EleoNora [17]

Answer: x=-63/73

Step-by-step explanation:

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6 0
3 years ago
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Describe and correct the error in finding the tenth term of the arithmetic sequence 4, 12, 20, 28.
ycow [4]

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

a_n = a_1 + d(n-1)

Plug in a_1 = 4, \ d = 8, \ n = 10 and you should get the following:

a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\

The tenth term is <u>76</u>

---------

We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}

---------

In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in a_n = a_1 + d(n-1) which shifts everything one spot to the left.

7 0
2 years ago
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