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Alik [6]
3 years ago
10

Find the minimum or maximum value of the function. What is the H? (Desmos)

Mathematics
1 answer:
beks73 [17]3 years ago
4 0

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3(x^{2}-4x)+16

=3(x^{2}-4x+4-4)+16   (- For the balance of equation, and attention 1)

=3(x-2)^{2}-3*4+16

=3(x-2)^{2}+4

<h3>Attention:</h3>

1. (a-b)^{2}=a^{2}  -2ab+b^{2}

2. The formula for the vertex form is y = a(x-h)^{2}+k, the vertex is (h,k)

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mart [117]
4 times will take you to cross
8 0
3 years ago
A six-sided die is rolled two times. What is the theoretical fractional probability that the first number is greater than the se
Alekssandra [29.7K]

Given:

A six-sided die is rolled two times.

To find:

The theoretical fractional probability that the first number is greater than the second number.

Solution:

If a six-sided die is rolled two times, then the total possible outcomes are 36.

S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

The outcomes where the first number is greater than the second number are

A = {(2,1), (3,1), (3,2), (4,1), (4,2), (4,3), (5,1), (5,2), (5,3), (5,4), (6,1), (6,2), (6,3), (6,4), (6,5)}

So, the favorable outcomes = 15.

Now, the theoretical fractional probability that the first number is greater than the second number is

Probability=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

Probability=\dfrac{15}{36}

Probability=\dfrac{5}{12}

Therefore, the required probability is \dfrac{5}{12}.

5 0
3 years ago
If F(x)=2 and g(x)=x^2+1,what is g(3)+f(4)
notka56 [123]

Answer:

12

Step-by-step explanation:

for g(3) replace x with 3 and for f(4) since f(x) is a constant function the value won't change so you put 2 then add both functions up

g(3) = 3^2 + 1 ➡ 10

f(4)= 2

10 + 2 = 12

4 0
3 years ago
How would u do 1 over 3 y + 1 over 4 = 5 over 12? I forgot my notes:(
malfutka [58]
Is it
\frac{1}{3y} + \frac{1}{4} = 5
or
\frac{1}{3} y + \frac{1}{4} = 5
?

both start out the same, just remember what you do to one side you have to do to the other, so subtract both sides by 1/4, then you want to get y alone, so either divide or multiply the 3 on both sides! let me know which it is and I can help you out more

[edit] it's the second, and not going to use cross multiplication.
added a picture that walks you through it :)

3 0
3 years ago
Taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.
Novosadov [1.4K]

Answer:

Step-by-step explanation:

Given that taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.

For a random single taxi std deviation is 2.20

But for a sample of size 10, std deviation would be

\frac{2.20}{\sqrt{10} }

This would be less than the 2.20

Because std devition is less for sample we get a big z score for the sample than the single.  

As positive values of z increase we find that probability would decrease since normal curve is bell shaped.

So single taxi fare would have higher probability than sample.

B) Here >24.

By the same argument we have z value less for single taxi hence the probability for more than that would be less than that of sample size 10

3 0
3 years ago
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