Question

Find the minimum or maximum value of the function. What is the H? (Desmos)

Answer 1

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3($x^{2}$-4x)+16

=3($x^{2}$-4x+4-4)+16   (- For the balance of equation, and attention 1)

=3$(x-2)^{2}$-3*4+16

=3$(x-2)^{2}$+4

Attention:

1. $(a-b)^{2}=a^{2} -2ab+b^{2}$

2. The formula for the vertex form is y = $a(x-h)^{2}+k$, the vertex is (h,k)