The sum of two numbers is 20 and their difference is 4. Which is the greater of the two numbers? The answer is 12.
Answer:
x > -4
Step-by-step explanation:
— 3х + 7 < 19
Subtract 7 from each side
— 3х + 7-7 < 19-7
-3x < 12
Divide each side by -3, remembering to flip the inequality
-3x/-3 > 12/-3
x > -4
Answer:
s = 15 over 2 (15/2 fraction) or 7.5
Answer:
150
Step-by-step explanation:
To solve the problem, put 5 instead of x, so 5*3
and put 10 instead of y, so 10*1
when combined,
(5*3) * (10*1)
= 15 * 10
= 150
Hope this helps!!
Let me know if I'm wrong...
You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
