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Reika [66]
3 years ago
10

50 POINTS | I NEED FULL STEP BY STEP ANSWER FOR EACH PROBLEM

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0

Answer:

Step-by-step explanation:

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At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes
lakkis [162]

Answer:

The calculated  |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Mean of the Population = 1900

Given random sample size 'n' =  45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

<u><em>Null Hypothesis</em></u>:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

<u><em>Alternative Hypothesis</em></u> :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

<u><em>Step(ii</em></u>):-

Test statistic

        t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

        t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }

       t = -900 /33.54 = -26.517

      |t| = |-26.517|=26.517

Degrees of freedom

                       γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated  |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

4 0
3 years ago
How do you do this question?
katovenus [111]
<h3>4 Answers: A, C, E, and F</h3>

================================================

Explanation:

Choice A is true assuming we have a_n = (-1)^n*b_n

In this case, a_n = (-1)^n*\frac{1}{\sqrt{n}} and b_n = \frac{1}{\sqrt{n}}

--------

Choice B is false. See choice A above.

--------

Choice C is true. The sequence \{b_n\} is decreasing. As n gets larger, b_n gets smaller. This is because the denominator is growing larger with the numerator held constant.

--------

Choice D is false. This contradicts choice C.

--------

Choice E is true since the denominator is growing forever

This is similar to  \displaystyle \lim_{n \to \infty} \frac{1}{n} = 0

--------

Choice F is true due to choices C and E being true.  

--------

Choice G is false because it contradicts choice F.

8 0
4 years ago
Mr and Mrs jackson are having a family portraits taking with their son and daughter. the photographer wants to have two people s
miskamm [114]
If your question is how many positions are possible, then the answer is 24.

We find this by thinking of how many people can be in each spot. If there are 4 spots each person can stand (back left, back right, front left, front right), then there are 4 possible choice for the first spot (mom, dad, son, daughter), then 3 for the next spot (since 1 is already in a spot), then 2 options for the next spot, and then 1 option for the last spot. In other words, the answer is 4x3x2x1, or 4 factorial.
5 0
3 years ago
What is 25 and (2/3) minus (2/3)
icang [17]
25 because you would just get rid of the 2/3

4 0
4 years ago
Read 2 more answers
Rohan did a survey in four bird parks and wrote the following observations:
stiks02 [169]

Answer:  Park P

Step-by-step explanation:

Since, According to the question,

Number of yellow bird in park P = 33

Total number of the bird in park P = 53

Thus, the percentage of yellow bird in park P = \frac{33}{53} \times 100= 62.264150943% ≈ 62 %

Number of yellow bird in park Q = 20

Total number of the bird in park Q = 48

Thus, the percentage of yellow bird in park P = \frac{20}{48} \times 100=41.666666666% ≈ 42%

Number of yellow bird in park R = 54

Total number of the bird in park R = 90

Thus, the percentage of yellow bird in park R = \frac{54}{90} \times 100= 60 %

Number of yellow bird in park S = 44

Total number of the bird in park S = 83

Thus, the percentage of yellow bird in park P = \frac{44}{83} \times 100=53.012048192 % ≈ 53 %

Since, 62% > 60% > 53% > 42%

Therefore, highest percentage of the yellow bird is 62 %

Which is present in park P.

8 0
3 years ago
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