Answer:
hiii 7272<>*~_+89×[0<×<×*×
Step-by-step explanation:
a)
total no. of pupils is not more than 24
therefore first equation is
(x+y) ≤ 24. ....(1)
No. of girls exceeding the no. of boys by atleast 4
(y-x) ≥ 4. .....(2)
b) Now Liza chooses 8 boys
Maximum no. of girls = ?
Using first inequality
y+8= 24 ( maximum value of less than or equal to function is equal to itself)
Therefore,
y= 24-8
=16
Minimum no. of girls = ?
Using second inequality
y-8 =4 (minimum value of greater than or equal to function is equal to itself)
Therefore,
y= 4+8
y=12
Answer:
a) 2linear inequalities
(x+y) ≤ 24
(y-x) ≥ 4
b) Max no. of girls = 16
Min no. of girls = 12
Hope it helps...
Convert all to decimals
1/4=0.25
1/2=0.5 so
2 and 1/2=2.5
3=3
-1 and 1/4=-1.25
4 and 1/4=4.25
1 and 1/4=1.25
-1 and 1/2=-1.5
add all together
2.5+3-1.25+4.25+1.25-1.5=8.25=8 and 1/4
answer is 8 and 1/4
B is correct answer
(note, previous user's answer was correct, but had no work shown)
Answer:
$960
Step-by-step explanation:
1/5= .2
1-0.2= 0.8
1200×0.8= 960
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
